Olympia Kristallon HC357 Polycarbonate Ridged Jug With Cooling Tube Clear 1.6 Ltr (DISCONTINUED) DiscontinuedRecommended AlternativeOlympia Kristallon J904 Durable Polycarbonate Jug Clear 1.4 Ltr£7.99ex. VAT£9.59inc. VATModelDescriptionTechnical SpecsDescription MPNHC357 CAS SKU114314AKAHC357This 1600ml jug from the Olympia Kristallon collection is perfect for serving chilled drinks like water, fruit juices and iced tea. It features a central cooling tube that can be filled with ice cubes or frozen to keep your beverages refreshingly cold. The durable polycarbonate body is built to withstand the wear and tear of everyday use, indoors or outdoors. The jug's spout allows for fast, controlled pouring, and the entire construction is conveniently dishwasher-safe for easy cleaning.Features a central cooling tube which can be filled with ice cubes or frozenIdeal for serving cooled water, juices, ice teaJug is made from durable polycarbonate, lid is made from polypropyleneSpout provides fast and controlled pouringPerfect for indoor and outdoor useGlasswasher-safe construction allows for fast and thorough cleaningPack InformationPack Quantity1Product DimensionsDimensions213(H) x 154(W) x 154(D)mmWeightProduct Weight457gCapacityCapacity1.6 LtrConstructionMaterialPolycarbonateAppearanceColourClearWarrantyWarrantyManufacturers 1 Year Parts & Labour Back to BaseUnit ConvertorAre you eligible for more services?Please enter your postcode and click Submit to find outUnit converterFor your convenience we have provided a unit conversion table.All you need to do is enter the known value for any given unit, then the table will automatically convert it into the other units. It couldn't be easier.Length ConversionMillimeter [mm]:Centimeter [cm]:Meter [m]:Inch [in]:Foot [ft]:Yard [yd]:Weight ConversionMilligram [mg]:Gram [g]:Kilogram [kg]:Ounce [oz]:Pound [lb]:Volume and Capacity ConversionMilliliter [mL]:Liter [L]:Ounce [fl oz]:Cubic Centimeter [cm3]:Cubic Meter [m3]:Cubic Foot [ft3]:Gallon [gal]:Have a Question?Name:Email Address:Your Question: