Polar AE695 Water Inlet PipeCAS SKU34166MPNAE695AKAAE695RRP: £10.99 exc. vat 13.19 inc. vat SAVE: £2.00 exc. vat 2.40 inc. vat WAS: £12.99 exc. vat 15.59 inc. vat £10.79 inc. vat £8.99 exc. vat inc. vatexc. vatIn Stock Total Price: Add to BasketAdd to QuoteView Compare Compare | Share | Wishlist 1-2 Working Days Delivery Product SpecificationsSpare TypePipes, Tubes & HosesDimensions1500(L)mmProduct Weight250gColourBlueWarrantyN/AUnit Convertor Details Compatible Units Delivery FAQ's DetailsAE695 Water Inlet PipePolar AE695 FeaturesDimensions: 1500(L)mmWeight: 250gFitting: 3/4"Colour: BlueWRAS approved Compatible UnitsPolar G-Series GD887 Automatic Self Contained Cube Ice Machine(25kg/24hrs)SKU1037MPNGD887DiscontinuedPolar G-Series GD888 Automatic Self Contained Cube Ice Machine (45kg/24hrs) SKU1039MPNGD888DiscontinuedPolar G-Series GL192 Automatic Self Contained Ice Machine with Drain Pump (50kg/24hr)SKU23772MPNGL192Polar G-Series T316 Automatic Self Contained Ice Machine (20kg/24hr)SKU833MPNT316 Delivery Options (Select during checkout)Delivery IconCostServiceEst Delivery DateInfoEst Delivery Date ExpiresCost:£9.95 +VAT Service:Order by 5pm for1-2 Working Days DeliveryEstimated Delivery Date:Tue 28th April to Wed 29th AprilService Expires:5:00pm on Mon 27th April Please note the following:All items over 30kg are kerbside delivery only,Deliveries take place between the hours of 7am and 6:30pm FAQNo questions have been submitted yetAsk a QuestionUnit converterFor your convenience we have provided a unit conversion table.All you need to do is enter the known value for any given unit, then the table will automatically convert it into the other units. It couldn't be easier.Length ConversionMillimeter [mm]:Centimeter [cm]:Meter [m]:Inch [in]:Foot [ft]:Yard [yd]:Weight ConversionMilligram [mg]:Gram [g]:Kilogram [kg]:Ounce [oz]:Pound [lb]:Volume and Capacity ConversionMilliliter [mL]:Liter [L]:Ounce [fl oz]:Cubic Centimeter [cm3]:Cubic Meter [m3]:Cubic Foot [ft3]:Gallon [gal]: Have a Question? Name: Email Address: Your Question: